I have hot air source from grate cooler at 250 degree @ 190000 m3/hr. I have a ball mill with auxiliary furnace whose tph is 9 tph with coal input moisture of 10% . The fine coal moisture is 1 %. CV of coal is 7000 kcal / kg coal. How can I calculate the saving of coal if i use this hot air & stop the auxiliary furnace? raj
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Re: coal savings
It needs 58.5 GJ to heat 190000 Nm³ from 20°C to 250°C .
If your coal heat value is 27 GJ/t , 58.5 GJ represent 2.17 t coal.
(did you mean Nm³ or actual m³ in your post ?)
However, in principle, it is not possible to answer your question without knowing more about the milling/drying plant you are considering. See this thread .
also do not understand your question very well. What are these 9 tph of coal? Are these the quantity of coal you burn in the dryer, or is it the quantity of coal you need to dry ? Ideally, you should better include a drawing in your post.
It is quite possible that 190000 Nm³/h is more than what you need to burn the coal you need for drying purpose. To burn 1 ton of coal, you need (stoechiometrically) typically 8500 Nm³ of air or 16000 Nm³ for 10%O2 in the exhaust.
Finally, note that using hot air directly to dry coal might be very dangerous.
Re: coal savings
9 tph is the capacity of coal mill means the output of coal mill . I do not know the amount of coal fired in the auxiliary furnace. my question is how can i calculate the amount of coal i am using in the auxiliary furnace and that amount of coal will be saved by the use of hot air from the cooler. please send me in detail firstname.lastname@example.org