xxxx
239 posts
TimePosted 29/03/2011 12:26:29
xxxx says

Re: fan aerolic power calculation

iIF U PUT Pa = 1mmwg/9.81 in Watt = Pa * m3/s than Watt = mmwg*m3/s divided by 9.81 Than kiloWatt = mmwg * m3/s /( 1000*9.81) pl. comment

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chari
79 posts
TimePosted 30/03/2011 06:28:49
chari says

Re: fan aerolic power calculation

Mr xxxx

since you are taking the reading in mmwg ,you have to multiply 9.81 to convert it to Pa then divide it by 1000 to get Kw. you are doing in a reverse way.

The Kw calculation is nothing but work done per second

and work done is always the air handled and pressure

rectify  dear

chari

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xxxx
239 posts
TimePosted 30/03/2011 07:20:00
xxxx says

Re: fan aerolic power calculation

no i am not doing the reverse way. just see 1 mmwg = 9.81 Pa than Pa = 1mmwg / 9.81 than put the value of Pa in the formula = Pa * volume (m3/s) it becomes watt = (mmwg/9.81) * volume (m3/s) so u do not get 102 in denomenator pl. check

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chari
79 posts
TimePosted 30/03/2011 07:52:06
chari says

Re: fan aerolic power calculation

Let us take an example of a fan

Pressure = 5393 Pa, Volume =21.1m3/sec KWatt = 5393*21.1/1000 = 113.7 Kw

Now converting pascal to mmwg by deviding 9.81

pressure = 550mmwg , Volume =21.1m3/sec KWatt = 550*21.1/102= 113.7 Kw

1mmwg = 9.81Pa

Then 2mmwg = 19.62 Pa

X mmwg = X * 9.81 Pa, it will be a multiplication not devidation, i Think you are clear from the data

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